Final answer:
To model the given data, we use quadratic regression and find that the function T(t) = -0.5t^2 + 11.8t + 63.86 best fits the data. By substituting t = 8 into the function, we predict that the temperature in May is approximately 68.46 degrees.
Step-by-step explanation:
To create a function that models the given data, we can use the concept of regression. Let's assume that the temperature is a function of time, represented by T(t). We can plot the given data points on a graph and try to find a function that best fits the data. In this case, a quadratic function seems to be a good fit:
T(t) = -0.5t^2 + 11.8t + 63.86
To predict the temperature in May, we substitute t = 8 (since May is 8 months from August) into the function:
T(8) = -0.5(8)^2 + 11.8(8) + 63.86 = 68.46
Learn more about Quadratic regression