To calculate the percent yield, we need to compare the actual yield (15.0 grams of water) to the theoretical yield. The balanced equation shows that for every 2 moles of oxygen, we should get 2 moles of water.
First, we need to convert the grams of oxygen to moles. Using the molar mass of oxygen (O2), which is approximately 32 g/mol, we can calculate the number of moles of oxygen.
- 42.5 grams of oxygen * (1 mol/32 g) = 1.328125 moles of oxygen
Since the balanced equation shows a 1:1 ratio between moles of oxygen and moles of water, the theoretical yield of water is also 1.328125 moles.
Now, we can calculate the percent yield using the formula:
- Percent Yield = (Actual Yield / Theoretical Yield) * 100
- Percent Yield = (15.0 g / (1.328125 mol * 18 g/mol)) * 100
- Percent Yield = (15.0 g / 23.90625 g) * 100
- Percent Yield = 62.74%
Therefore, the percent yield is approximately 62.74%.