Question

The vertices of JKL are J(–1, 4), K(, –5), and L( 2). The triangle is reflected over the line y x. Graph JKL and J'K'L'

Answer 1

It seems there might be a typo in the coordinates of point K. Assuming it is K(x, -5), let's proceed with that.

The reflection over the line \(y = x\) involves swapping the x-coordinates with the y-coordinates. Here are the original and reflected coordinates:

Original Triangle JKL:
- J(-1, 4)
- K(x, -5)
- L(2, ?) - There is a missing coordinate for L.

Reflecting over \(y = x\):
- J'(4, -1)
- K'(-5, x)
- L'(? , 2) - The y-coordinate of L is swapped with the x-coordinate.

To provide a more accurate reflection, we would need the correct y-coordinate for point L. Please provide that information, and I can help you complete the reflection accurately.