Question

What is Ca(CH3COO)2 total atoms

Answer 1

The compound Ca(CH3COO)2 consists of one calcium atom (Ca), two acetate ions (CH3COO-), and a total of 14 atoms. To determine this, you can count the atoms by multiplying the subscript of each element by the number of that element in the compound.

In this case, there is one calcium atom (Ca), two acetate ions, each consisting of three carbon atoms (C), two hydrogen atoms (H), and four oxygen atoms (O). Adding them all up: 1(Ca) + 2(CH3COO) = 1 + 2(3C + 3H + 2O) = 1 + 2(8) = 17 atoms. However, since there are two acetate ions, we need to multiply the total by 2, resulting in a total of 34 atoms.

Answer 2

15 atoms

To determine the total number of atoms in Ca(CH3COO)2, we need to consider the individual elements in the compound and their respective subscripts.

In Ca(CH3COO)2, we have:

- 1 calcium atom (Ca)

- 2 acetate ions (CH3COO). Each acetate ion consists of:

- 2 carbon atoms (C)

- 3 hydrogen atoms (H)

- 2 oxygen atoms (O)

Let's calculate the total number of atoms:

1 calcium atom (Ca)

2 acetate ions * (2 carbon atoms + 3 hydrogen atoms + 2 oxygen atoms)

= 1 calcium atom + 2 * (2 carbon atoms + 3 hydrogen atoms + 2 oxygen atoms)

Simplifying the expression:

= 1 calcium atom + 4 carbon atoms + 6 hydrogen atoms + 4 oxygen atoms

Therefore, the total number of atoms in Ca(CH3COO)2 is 1 calcium atom + 4 carbon atoms + 6 hydrogen atoms + 4 oxygen atoms, which equals 15 atoms.