Answer:
The typical pace of progress of the capability y = f(x) on the stretch 3 ≤ x ≤ 4 is (10(- 10))/(4-3)= 20/1 = 20.
Explanation:
To find the typical pace of progress on the span [3, 4], you can utilize the equation:
\[ \text{Average Pace of Change} = \frac{f(4) - f(3)}{4 - 3} \]
Take a gander at the diagram and find the relating y-values for \(x = 3\) and \(x = 4\). When you have those qualities, substitute them into the recipe to work out the normal pace of progress.