Question

Complete the square to write 16t2 - 96t+48 = 0 as
DONE
DEUENDO C
9 of 9

Answer 1

To complete the square for the quadratic equation 16t^2 - 96t + 48 = 0, divide the equation by the coefficient of t^2, add the square of half the coefficient of t, and solve for t.

Step-by-step explanation:

To complete the square for the quadratic equation 16t^2 - 96t + 48 = 0, we follow these steps:

1. Divide the equation by the coefficient of t^2 to make the leading coefficient 1. The equation becomes t^2 - 6t + 3 = 0.
2. Take half of the coefficient of t, square it, and add it to both sides of the equation. This completes the square for the t terms. The equation becomes (t - 3)^2 = 6.
3. Take the square root of both sides of the equation to solve for t. The solutions are t = 3 + √6 and t = 3 - √6.

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