Question

A 0.08 kg soccer ball at rest is kicked and flies through the air with a speed of 40 m/s. What type of collision did the objects (the ball and the foot) experience, and how did the forces on each compare?

Answer 1

Elastic collision and the force on each was the same

Step-by-step explanation:

The collision between the ball and the foot is an elastic collision. This is because both the kinetic energy and the momentum of the system are conserved.

To calculate the force on the ball, we can use the following equation:

`\boxed{\boxed{\sf F = m a}}`

where:

• F is the force in Newtons
• m is the mass in kilograms
• a is the acceleration in meters per second squared

We know that the mass of the ball is 0.08 kg and the acceleration is 40 m/s². Let's solve for the force:

F = 0.08 kg × 40 m/s²

F = 3.2 N

Therefore, the force on the ball is 3.2 N.

Since the collision is elastic, the force on the foot must be equal to the force on the ball. This is because the momentum of the system is conserved.

Conclusion

The ball-foot system experienced an elastic collision. The force on each was the same, which is 3.2 N.