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8x+12y=108 in slope-intercept form

User Riemannzz
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Final answer:

To write the equation 8x+12y=108 in slope-intercept form, subtract 8x from both sides and divide by 12 to solve for y. The slope-intercept form of the equation is y = (-2/3)x + 9.


Step-by-step explanation:

To write the equation 8x+12y=108 in slope-intercept form, which is y=mx+b, we need to solve for y.

First, let's isolate y by subtracting 8x from both sides of the equation:

12y = -8x+108

Next, divide both sides of the equation by 12 to solve for y:

y = (-8/12)x + 9

Now, we can simplify the equation by reducing the fraction: y = (-2/3)x + 9.

This is the slope-intercept form of the equation.


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User Seungah
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