Question

a stone weighing 0.5 kg tied to a rope of length 0.5 m revolves along a circular path in a vertical plane. the tension of the rope at the bottom point of the circle is 45 newton. to what height will the stone rise if the rope breaks at the moment when the velocity is directed upwards? (g

Answer 1

The stone will rise to a height of 1 meter when the rope breaks.

Step-by-step explanation:

To calculate the height to which the stone will rise when the rope breaks, we need to consider the tension and weight of the stone. At the bottom point of the circle, the tension is 45 Newton, which is equal to the weight of the stone. Therefore, we can use the formula T = mg, where T is the tension, m is the mass, and g is the acceleration due to gravity.

Since the tension is equal to the weight, T = mg = 0.5 kg * 9.8 m/s² = 4.9 Newton. This means that the stone will rise to a height where it has a potential energy of 4.9 Joule. We can calculate this height using the formula for potential energy: PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Solving for h, we have h = PE / (mg) = 4.9 J / (0.5 kg * 9.8 m/s²) = 1 meter.

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