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4 votes
6 ft

8 ft
find the surface
area of the
regular pyramid.
round to nearest
tenth.

6 ft 8 ft find the surface area of the regular pyramid. round to nearest tenth.-example-1

1 Answer

4 votes

Answer:

Explanation:

The surface area consists of an equilateral triangle of sides 6 ft and 3 (the base) and 3 side isosceles triangles of height 8 ft.

Area of the 3 side triangles

= 3 * 1/2 * 6 * 8

= 72 ft^2.

Area of the base = 1/2* 6 * height

Height = √(6^2 - 3^2)

= √27

Area of base = 1/2 * 6 * √27

= 15.588 ft^2.

Total surface area

= 87.6 ft^2 to the nearest tenth.

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