Answer:
Explanation:
The value of √110 is between two consecutive integers
so first find the two consecutive perfect squares that √110 lies between. Since 10^2 = 100 and 11^2= 121, we know that √110 lies between 10 and 11.
Round down to the lower integer to get the lower bound. So, the lower bound is 10.
Round up to the higher integer to get the upper bound. Therefore, the upper bound is 11.
So the value of √110 is between 10 and 11.