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Consecutive Integer Problems - Linear (Level 2)

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Question
The sum of an integer and 4 times the next consecutive even integer is 58.
Find the value of the greater integer.
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Answer 1

The sum of an integer and 4 times the next consecutive even integer is 58. The value of the greater integer is 12.

Step-by-step explanation:

Let's denote the first integer as x. The next consecutive even integer would be x+2. According to the given information, the sum of x and 4 times the next consecutive even integer (x+2) is equal to 58. We can write this as the equation: x + 4(x+2) = 58.

Simplifying the equation, we get: x + 4x + 8 = 58.

Combining like terms, we have: 5x + 8 = 58.

Subtracting 8 from both sides, we get: 5x = 50.

Dividing both sides by 5, we find: x = 10.

Therefore, the value of the greater integer is x+2 = 10+2 = 12.

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