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The cockroach population in a particular apartment building can be approximated by an exponential function, with a growth rate of 3.2% per month. After about how many months will the population double, to the nearest month?

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Answer:

22 months

Explanation:

To solve this problem, we can use the following formula for exponential growth:


\boxed{\boxed{\sf A = P(1 + r)^t }}

where:

  • A is the final population
  • P is the initial population
  • r is the growth rate
  • t is the time in years

Let the initial population is P = x cockroaches, the growth rate is r = 3.2% = 0.032 per month, and we want to find the time t in months when the population doubles, which means A = 2P = 2x cockroaches.

Substituting these values into the formula, we get:


\sf 2x = x (1 + 0.032)^t


\sf 2 \cdot \cancel{x}=\cancel{x} ( 1.032)^t


\sf 2 = ( 1.032)^t

Taking the logarithm of both sides (in base 10), we get:


\sf log(2) = t log(1.032)

Dividing both sides by log(1.032), we get:


\sf t =( log(2) )/( log(1.032))

Evaluating this expression, we get:


\sf t = 22.005603578508

In nearest month

t = 22 months

Therefore, the cockroach population will double after about 22 months.

User Thibauts
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