Answer : 34th term is 265
Given the following sequence
1, 9, 17, 25, 33
Firstly, we need to find the common difference of the series
Common difference = Larger number - lower number
Common difference = 9 - 1 = 8
17 - 9 = 8
25 - 17 = 8
33 - 25 = 8
Therefore, the common difference = 8
Tn = a + (n - 1 ) d
Where a = first term, n = no of terms, d = common difference
a = 1, n = 34, d = 8
T34 = 1 + (34 - 1) x 8
T34 = 1 + (33) x 8
T34 = 1 + 264
T34 = 265
Therefore, the 34th term is 265