Question

Which of the following is an extraneous solution of √√-3x-2-x+2?

O x = -6
O x=-1
O x = 1
O x = 6
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Answer 1

An extraneous solution is a solution that does not satisfy the original equation when substituted back into it. In this case, the extraneous solutions for the given equation are x = 1 and x = 6.

Step-by-step explanation:

An extraneous solution is a solution that does not satisfy the original equation when substituted back into it. To determine which of the given options is an extraneous solution for the equation √√(-3x-2) - x + 2, we need to check if these solutions make the radicand (the expression inside the square root) negative.

Let's substitute each option into the radicand:

For x = -6:

-3(-6) - 2 = 16

The radicand is positive, so x = -6 is not an extraneous solution.

For x = -1:

-3(-1) - 2 = 5

The radicand is positive, so x = -1 is also not an extraneous solution.

For x = 1:

-3(1) - 2 = -5

The radicand is negative, so x = 1 is an extraneous solution.

For x = 6:

-3(6) - 2 = -20

The radicand is negative, so x = 6 is also an extraneous solution.

Therefore, the extraneous solutions for the given equation are x = 1 and x = 6.

Learn more about Extraneous solutions