Question

Solve the equation (the answer might be no solution or all real numbers)-30= -10(q-1)6+(c+8)=136-(c+8)=13-(c-4)=13-36= -3(2-5m)4-10(n+4)=-56

Answer 1

We have to find the solution for this equations.

a) -30 = -10(q-1)

`\begin{gathered} -30=-10(q-1) \\ q-1=(-30)/(-10) \\ q-1=3 \\ q=3+1 \\ q=4 \end{gathered}`

b) 6+(c+8) = 13

`\begin{gathered} 6+(c+8)=13 \\ c=13-6-8 \\ c=-1 \end{gathered}`

c) 6-(c+8)=13

`\begin{gathered} 6-(c+8)=13 \\ 6-13=c+8 \\ -7=c+8 \\ -7-8=c \\ c=-15 \end{gathered}`

d) -(c-4)=13

`\begin{gathered} -(c-4)=13 \\ c-4=-13 \\ c=-13+4 \\ c=-9 \end{gathered}`

f) -36= -3(2-5m)

`\begin{gathered} -36=-3(2-5m) \\ (-36)/(-3)=2-5m \\ 12=2-5m \\ 5m=2-12 \\ 5m=-10 \\ m=(-10)/(5) \\ m=-2 \end{gathered}`

g) 4-10(n+4)=-56

`\begin{gathered} 4-10\mleft(n+4\mright)=-56 \\ 4+56=10(n+4) \\ 60=10(n+4) \\ (60)/(10)=n+4 \\ 6=n+4 \\ n=6-4 \\ n=2 \end{gathered}`