Answer:
I'm going to teach you how to find the x- and y-intercepts of the line that passes through the points (-6,-6) and (9,-3).
First, we need to find the slope of the line. That's easy-peasy, lemon-squeezy. Just use this formula: m = (y2 - y1) / (x2 - x1). Plug in the coordinates of the points, and you get m = (-3 - (-6)) / (9 - (-6)) = 3 / 15 = 1 / 5. Wow, that's a nice slope!
Next, we need to find the y-intercept. That's the point where the line crosses the y-axis, or in other words, where x = 0. To do that, we can use the point-slope form of the equation of a line: y - y1 = m (x - x1). Pick any point on the line, and plug in the values. Let's use (-6,-6), because why not? We get y - (-6) = (1 / 5) (x - (-6)). Simplify that a bit, and you get y = (1 / 5) x - (6 / 5).
Now we have the y-intercept! It's just the constant term in the equation, or -6 / 5. That means the line crosses the y-axis at -6 / 5. Isn't that neat?
Finally, we need to find the x-intercept. That's the point where the line crosses the x-axis, or in other words, where y = 0. To do that, we can use the slope-intercept form of the equation of a line: y = mx + b. Plug in the values we already found, and we get 0 = (1 / 5) x - (6 / 5). Solve for x, and you get x = 6.
And there you have it! The x-intercept is 6, and the y-intercept is -6 / 5. And we've done it!