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A line passes through the point (0,6) and is parallel to the line with the equation y = 1∕5x – 5. What's the equation of the line?

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Answer:

To find the condition of a line lined up with \(y = \frac{1}{5}x - 5\) and going through the point \((0,6)\), you can utilize the way that equal lines have a similar slant. The given line has a slant of \(\frac{1}{5}\), so the equal line will likewise have a slant of \(\frac{1}{5}\).

The point-slant type of a line is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line and \(m\) is the slant. Subbing the qualities, you get \(y - 6 = \frac{1}{5}x - 0\). Presently, you can work on this to get the condition of the equal line.

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