Question

For what of 0, in degree, is sin= con 58⁰?

Answer 1

Answer: We want to find angle 'theta' for which:

`\sin (\theta)=\cos (58)`

In general, the following is always true:

`\cos (\theta)=\sin (90-\theta)\rightarrow(1)`

Therefore we have the following:

`\cos (58^(\circ))=\sin (90-58)=\sin (32^(\circ))`

Therefore the angles that we were interested in is:

`\theta=32^(\circ)`