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How many moles of nitrogen dioxide, NO2, are needed to react with 2.83 moles of water, H2O?

User Jujka
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Answer:

To decide the moles of nitrogen dioxide (\(NO_2\)) expected to respond with a specific measure of water (\(H_2O\)), you really want the fair compound condition for the response somewhere in the range of \(NO_2\) and \(H_2O\).

Since you haven't given the reasonable condition, I'll make a presumption in light of a typical response including nitrogen dioxide:

\[3NO_2 + H_2O \rightarrow 2HNO_3\]

This condition recommends a 3:1 molar proportion somewhere in the range of \(NO_2\) and \(H_2O\).

Presently, assuming that you have 2.83 moles of \(H_2O\), you can utilize the molar proportion to track down the moles of \(NO_2\):

\[ \text{Moles of } NO_2 = 2.83 \, \text{moles of } H_2O \times \frac{3 \, \text{moles of } NO_2}{1 \, \text{mole of } H_2O} \]

Compute this articulation to track down the moles of \(NO_2\) expected to respond with 2.83 moles of \(H_2O\).

User Krul
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