Question

Suppose a force F, = (1/3)x acts on anobject. Assume at x = 0 the force pushesthe object and it starts moving to the right.What happens to the magnitude of the workdone as the object moves to the right?A. More work is done B. Less work is doneC. A constant amount of work is doneD. It is impossible to predict

Answer 1

We are given that a variable force acts on an object given by the function:

`F_x=(1)/(3)x`

This force will increase as the object moves since the value of "x" will increase. The work done is defined as:

`W=Fd`

Where "F" is the force and "d" is the total distance. This magnitude will also increase therefore, more work is done.