Question

A line has a slope of

3
5
and passes through the point (11,6). Write its equation in slope-intercept form.

Answer 1

Solve for be and plug in points for y and x
y=3/5x+b
6=(3/5)(11)+b
6-33/5 = b
30/5 - 33/5 = b
b = -3/5

y=3/5x-3/5

Answer 2

To write the equation of a line in slope-intercept form, we need the slope and the y-intercept. In this case, the slope is 3/5 and the line passes through the point (11,6). Using the point-slope form, the equation is y = (3/5)x + (33/5).

Step-by-step explanation:

To write the equation of a line in slope-intercept form, we need the slope (m) and the y-intercept (b). The slope-intercept form of a linear equation is y = mx + b.

In this case, the slope is 3/5 and the line passes through the point (11,6). We can use the point-slope form of a linear equation to find the equation of the line. The point-slope form of a linear equation is y - y1 = m(x - x1).

Using the given point (11,6) and the slope 3/5, the equation in point-slope form is y - 6 = (3/5)(x - 11). To convert it to the slope-intercept form, we can simplify and isolate y. So, y = (3/5)x + (33/5).