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Write an equation in point-slope and slope-intercept forms that passes through the points (–4, 3.3) and (1, –9.7).

User Shreeraj
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Answer:

Explanation:

To write an equation in a point-slope form that passes through the points (–4, 3.3) and (1, –9.7), we can use the following formula:

y - y1 = m(x - x1)

Where m is the slope of the line and (x1, y1) is one of the given points 12.

First, we can find the slope of the line using the two given points:

m = (y2 - y1) / (x2 - x1)

= (-9.7 - 3.3) / (1 - (-4))

= -13 / 5

Therefore, the slope of the line is -13/5.

Next, we can choose one of the given points, say (–4, 3.3), and substitute the values into the formula:

y - y1 = m(x - x1)

y - 3.3 = (-13/5)(x - (-4))

y - 3.3 = (-13/5)(x + 4)

This is the equation of the line in point-slope form.

To write the equation in slope-intercept form, we can simplify the equation by solving for y:

y - 3.3 = (-13/5)(x + 4)

y = (-13/5)x - (52/5) + 3.3

y = (-13/5)x - (13/10)

Therefore, the equation of the line in slope-intercept form is

y = (-13/5)x - (13/10).

User Kchoi
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