Question

Calculate the change in pH that occurs when 0.010 mol gaseous HCl is added to 1.0 L of each of the following solutions: Solution A: 5.00MHC2H3O2 and 5.00MNaC2H3O2 Solution B: 0.050MHC2H3O2 and 0.050MNaC2H3O2

Answer 1

Answer:

Solution A

pH=4.76+log( 5.00-0.010/5.00+0.010)

pH≈4.758

So, the change in pH for Solution A is approximately -0.002.

Solution B

pH=4.76+log(0.667)

pH≈4.585

So, the change in pH for Solution B is approximately -0.175.