Final answer:
To solve the system of equations algebraically, substitute the value of y from one equation into the other two equations. Solve for x and substitute the values back to find the corresponding values of y. The solutions to the system of equations are (7, 7) and (-6, 6).
Step-by-step explanation:
To solve this system of equations algebraically, we can substitute the value of y from the second equation into the other two equations.
By substituting y into the first equation, we get x² - x - 48 = -x + 1. Solving this quadratic equation, we find that x = 7 or x = -6.
Substituting the values of x into the second equation, we can find the corresponding values of y. Therefore, the solutions to the system of equations are (7, 7) and (-6, 6).
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