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What is the equation of the line that passes through the points (-3,-2) and (1,6)?

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To find the equation of the line that passes through the points (-3,-2) and (1,6), we can use the slope-intercept form of a linear equation: y = mx + b.

First, let's calculate the slope (m) using the formula: m = (y2 - y1) / (x2 - x1).

Using the coordinates (-3,-2) and (1,6), we have:
m = (6 - (-2)) / (1 - (-3))
m = 8 / 4
m = 2

Now that we have the slope (m), we can choose any point on the line (let's use the point (-3,-2)) and substitute the values into the equation y = mx + b to solve for the y-intercept (b).

-2 = 2 * (-3) + b
-2 = -6 + b
b = 4

So, the equation of the line that passes through the points (-3,-2) and (1,6) is y = 2x + 4.
User Andrei Titov
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