Question

A 20.0 L gas cylinder contains 0.480 moles of H2 at 25.0 C. What is the pressure of the gas in mm Hg?

Answer 1

P=59.461728 kPa

Step-by-step explanation:

PV = nRt

V = 20L
n = 0.48 mol
T = 25 degrees C

T = 25 degrees C +273 K T = 298 K

P*20L = 0.48 mol *8.314L * kPa/(mol*K)* 298 K

20L * P = 1189.23456L *kPa

20L * P/20L = 1189.23456L * kPa/20L

= 59.461728 kPa