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If f(1)=160 and f(n+1)=-2f(n) what is f(4)?

User Cyberbit
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1 Answer

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To find the value of f(4), we can use the given recursive formula:

f(n+1) = -2f(n)

Starting with f(1) = 160, we can calculate the subsequent values:

f(2) = -2f(1) = -2 * 160 = -320
f(3) = -2f(2) = -2 * (-320) = 640
f(4) = -2f(3) = -2 * 640 = -1280

Therefore, f(4) is -1280.
User Alberto Rivera
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