Question

if a bowl of a weight of 1 lb gets thrown at a force of 1 Newton down at a height of 1.54 mile and including the earths gravity, will it get to maximum velocity or not, if not tell me the speed it will fall at​

Answer 1

220.16 meters

Explanation:

v = √(2 * g * h)

- v is the final velocity (in meters per second, m/s).

- g is the acceleration due to gravity (approximately 9.81 m/s² on the surface of the Earth).

- h is the height (in meters, m) from which the object falls.

convert the height from 1.54 miles to meters

1 mile = 1609.34 meters

1.54 miles ≈ 1.54 * 1609.34 meters ≈ 2477.28 meters

calculate the final velocity

v = √(2 * 9.81 m/s² * 2477.28 m) ≈ √(48613.45 m²/s²) ≈ 220.16 m/s

the object in free fall, subject only to gravity and not other forces accelerates due to gravity until it reaches its terminal velocity. terminal velocity is the maximum constant velocity that the object can achieve in free fall.

in this case, since you mentioned that the object is thrown from a height of 1.54 miles, it will indeed reach its terminal velocity during the fall. the previously calculated final velocity of approximately 220.16 meters per second is the object's terminal velocity, and it will fall at this constant speed once it reaches it.

the object will reach its terminal velocity of about 220.16 meters per second during the fall.