Question

Kira went to play miniature golf on Monday, when it cost $14 to rent the club and ball, plus $1 per game. Farid went Thursday, paying $6 per game, plus rental fees of $4. By coincidence, they played the same number of games for the same total cost. How many games did each one play? How much did each one spend?

Kira and Farid each played games and spent $.

Answer 1

Kira and Farid each played 2 games and spent $16.

Explanation:

Let x be the number of games played by Kira and Farid.

The cost for Kira is:

= Cost of rent + rate per game

`\sf = \$14 + x * \$ 1`

`\sf = 14 + x`

The cost for Farid is:

= Cost of rent + rate per game

`\sf = \$4 + x * \$6`

`\sf = 4 + 6x`

We know that the costs are equal, so we can set up an equation:

14 + x = 4 + 6x

Subtracting x and 4 on both sides:

14 + x - x - 4 = 4 + 6x - 4 - x

10 = 5x

Dividing both sides by 5.

`(10)/(5)=(5x)/(5)`

2 = x

x = 2

So, Kira and Farid each played 2 games.

The cost for Kira is:

`\sf \$14 + 2* \$1 = \$16`

The cost for Farid is:

`\sf \$4 + 2* \$6 = \$16`

So,

Kira played 2 games and spent $16.

Farid played 2 games and spent $16.