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Y=(x+4)^2+4 to vertex form to standard form

1 Answer

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Answer:

Standard form: y = x^2 + 8x + 20

Explanation:

General equation of the vertex form:

The general equation of the vertex form of a quadratic is given by:

y = a(x - h)^2 + k, where:

  • a is a constant determining whether,
  • and (h, k) are the coordinates of the vertex.

General equation of the standard form:

The general equation of the standard form of a quadratic is given by:

y = ax^2 + bx + c, where:

  • a, b, and c are constants.

Converting from vertex form to standard form:

Thus, we can convert to vertex form by expanding (x + 4)^2 and combining all like terms:

y = (x + 4)(x + 4) + 4

y = (x^2 + 4x + 4x + 16) + 4

y = x^2 + 8x + 20

Therefore, y = x^2 + 8x + 20 is the standard form of the quadratic, given that y = (x + 4)^2 + 4 is its vertex form.

Note that another way to write the equation in standard form is by setting y equal to 0:

0 = x^2 + 8x + 20.