Question

For one type of insulating material, the temperature of the water decreased from 85.0c to 65.0c the energy transferred from the water was 10.5kj. specific heat capacity of water = 4200 kgc calculate the mass of the water in the can.

Answer 1

The mass of the water in the can is approximately 0.014 kg.

Step-by-step explanation:

To calculate the mass of water in the can, we can use the formula: Energy transferred = mass of water * specific heat capacity of water * change in temperature. Rearranging the equation gives us: mass of water = energy transferred / (specific heat capacity of water * change in temperature). Plugging in the given values, we get: mass of water = 10.5 kJ / (4200 J/kg/°C * (85.0°C-65.0°C)). So, the mass of the water in the can is approximately 0.014 kg.

Answer 2

The mass of the water in the can is 0.25 kg.

Step-by-step explanation:

The energy transferred from the water (\(Q\)) can be calculated using the formula
`\(Q = mc \Delta T\),` where \(m\) is the mass of the water, \(c\) is the specific heat capacity of water, and \(\Delta T\) is the change in temperature.

Given the specific heat capacity of water (\(c = 4200\) J/kg°C), the initial temperature (\(T_1 = 85.0°C\)) and final temperature (\(T_2 = 65.0°C\)), and the energy transferred (\(Q = 10.5\) kJ), rearrange the formula to solve for \(m\).

First, convert the energy from kilojoules to joules: \(10.5 \, \text{kJ} = 10.5 \times 10^3 \, \text{J}\). Then, plug in the values into the formula:

`\[Q = mc \Delta T\]\[10.5 * 10^3 \, \text{J} = m * 4200 \, \text{J/kg°C} * (85.0°C - 65.0°C)\]`

Solving for \(m\):

`\[m = \frac{10.5 * 10^3 \, \text{J}}{4200 \, \text{J/kg°C} * 20.0°C}\]\[m = \frac{10.5 * 10^3 \, \text{J}}{84000 \, \text{J/kg}}\]\[m = 0.125 \, \text{kg} = 125 \, \text{g}\]`

Therefore, the mass of the water in the can is 0.25 kg.

Understanding the relationship between energy transfer, specific heat capacity, and temperature change is essential in determining the mass of a substance involved in heat transfer processes.