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Please help with this, thanks. WILL GIVE 50 POINTS

Please help with this, thanks. WILL GIVE 50 POINTS-example-1

1 Answer

3 votes

Answer:

Area = 1032 sq. in.

Perimeter = 146 in

Explanation:

Part a.

To find the area of the trapezoid, we use the formula:


\boxed{\boxed{\sf Area = (1)/(2)\textsf{ (Base 1 + Base 2) }\cdot Height}}

where

  • Base 1 = 61 in,
  • Base 2 = 25 in, and
  • Height = 24 in.

Substituting the values and simplifying it.


\begin{aligned} \sf Area & = (1)/(2) (61 in + 25 in) \cdot 24 in \\\\ & = (86)\cdot 12 \\\\ & = 1032 in^2 \end{aligned}

And

To find the perimeter of the trapezoid, we add up all the side lengths.

The side lengths are 30 in, 30 in, 61 in, and 25 in.

Plugging in the values, we get:

Perimeter = 30 in + 30 in + 61 in + 25 in

Perimeter = 146 in


\cline

Part b.

The frame has to do with the perimeter of the picture because the frame adds extra material to the sides of the picture. The glass, on the other hand, has to do with the area of the picture because it covers the entire surface of the picture.


\cline

a. The area of the picture is
\boxed{ \sf 1032} sq in. and the perimeter is
\boxed{ \sf 146} in.

User Suza
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