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Line c has an equation of

y=-3/4x-3 Line d, which is parallel to line c, includes the point (-2,-2). What is the equation of line d?

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Answer:

To find the equation of a line parallel to line c, we can use the fact that parallel lines have the same slope.

The equation of line c is given as y = -3/4x - 3, where the coefficient of x (-3/4) represents the slope.

Since line d is parallel to line c, it will have the same slope of -3/4.

Now we have the slope (-3/4) and a point on line d (-2, -2).

Using the point-slope form of a linear equation, we can substitute the values into the formula to find the equation of line d.

The formula is: y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.

Substituting the values into the formula:

y - (-2) = -3/4(x - (-2))

Simplifying, we have:

y + 2 = -3/4(x + 2)

Expanding the brackets:

y + 2 = -3/4x - 6/4

Combining like terms:

y + 2 = -3/4x - 3/2

To make the equation easier to read, we can multiply through by 4 to get rid of the fraction:

4(y + 2) = 4(-3/4x - 3/2)

Simplifying, we have:

4y + 8 = -3x - 6

Rearranging the equation to match the standard form (Ax + By = C), we get:

3x + 4y = -14

Therefore, the equation of line d is 3x + 4y = -14.

Explanation:

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