137,972 views
19 votes
19 votes
No clue on how to do these or how to show all my work and unit cancellations.

No clue on how to do these or how to show all my work and unit cancellations.-example-1
User Joep
by
2.8k points

1 Answer

20 votes
20 votes

Question 16:

We are given the following balanced equation: (Remember to always balance the equation)


2HNO_3+Mg(OH)_2\rightarrow Mg(NO_3)_2+2H_2O

We are also told that Mg(OH)2 is in excess, meaning HNO3 is the limiting reactant, we will use its moles to find the number of moles of Mg(NO3)2, then we can convert that to mass.

The ratio between HNO3 and Mg(NO3)2 is 2:1

Therefore the number of moles of Mg(NO3)2 = 8.00 mol x (1/2) = 4.00 mol

Now we can convert the number of moles of Mg(NO3)2 to mass: molar mass of Mg(NO3)2 = 148,3 g/mol


\frac{8.00\text{ mol x 1}}{2}\text{ x }\frac{148.3\text{ g}}{1\text{ mol}}\text{ = 592 g}

So the mol will cancel the mol, then you will be left with g.

User DreadAngel
by
2.2k points