Answer:
Step-by-step explanation:
From the information given;
The velocity of the wind blow V = 7 m/s
The diameter of the blades (d) = 80 m
Percentage of the overall efficiency
![\eta_(overall) = 30\%](https://img.qammunity.org/2022/formulas/engineering/college/cuuk8ckhqrlmr4qgk8zygixv1r5lejjdu2.png)
The density of air
![\rho = 1.25 kg/km^3](https://img.qammunity.org/2022/formulas/engineering/college/stvdme73703acer266053hevkl856vt8fx.png)
Then, we can use the concept of the kinetic energy of the wind blowing to estimate the mechanic energy of air per unit mass by using the formula:
![e_(mechanic) = (mV^2)/(2)](https://img.qammunity.org/2022/formulas/engineering/college/ootnmwo5saj0zbx6zbjh6uvqz4v3lctpkw.png)
here;
m =
![\rho AV](https://img.qammunity.org/2022/formulas/engineering/college/dnctjsv7krrwhb1h2qdrcw116sbnpgwm17.png)
=
![1.25 * (\pi)/(4)(80)^2 * 7](https://img.qammunity.org/2022/formulas/engineering/college/uyexbdmeetrebvqbkchykrho2hm1p9t945.png)
= 43982.29 kg/s
∴
![W = e_(mechanic) = (mV^2)/(2)](https://img.qammunity.org/2022/formulas/engineering/college/579sye27argm9ojzzu2o94i9rom6e38qs7.png)
![= (43982.29 * 7^2)/(2)](https://img.qammunity.org/2022/formulas/engineering/college/rnmunae0krjedmqfwfr9ek1drkr8svlm0l.png)
![= 1077566.105 \ W](https://img.qammunity.org/2022/formulas/engineering/college/qg4k39c98fjzwnp4d189yfwldgo037ynct.png)
![\mathbf{ =1077.566 \ kW}](https://img.qammunity.org/2022/formulas/engineering/college/yk2m4v8zuaqi37d473xqd09w3auk00e0r2.png)
The actual electric power is:
![W_(electric) = \eta_(overall) * W](https://img.qammunity.org/2022/formulas/engineering/college/nrocwfdjtxnkwxi5wq4hoviwsjq9wurr4m.png)
![W_(electric) = 0.3 * 1077.566](https://img.qammunity.org/2022/formulas/engineering/college/j08kk9tv0g8q5kmbi1kxtrzsvsoe4s4lp6.png)
![\mathbf{W_(electric) =323.26 \ kW}](https://img.qammunity.org/2022/formulas/engineering/college/eb8modrkdisqhxpl8y86p3dhmmo89mrbbx.png)