Question

What is the equation of the line with

a slope of 4 that passes through the
x-axis at -3?
F y = 4x - 3
Gy= 4x + 3
Hy = 4x - 12
Jy = 4x+12

Answer 1

J: y=4x+12

for this equation, you'd use y=mx+b, or slope-intercept form.

the slope is given

plug in (-3,0) into the equation and solve for b.

using (-3,0) and the slope (4), we get

0 = 4(-3) + b

Simplify!

0 = -12 + b

when isolating b, add 12 to both sides of the equation

12 = b

your equation would be y=4x+12, which is answer choice J.