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I got 0.009 and I was wondering if that is right

I got 0.009 and I was wondering if that is right-example-1
User Kecman
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1 Answer

24 votes
24 votes

Step-by-step explanation:

The equation of formation of NO₂

1/2 N₂ (g) + O₂ (g) <----> NO₂ (g)

The equilibrium for the above reaction can be calculated using this equation:

Kc = [NO₂]/([N₂]^(1/2)*[O₂]) where the concentrations are the equilibrium concentrations.

According to the graph the concentration in the equilibrium of each compound is:

[NO₂] = 6 mol/L

[N₂] = 10 mol/L

[O₂] = 20 mol/L

If we replace these values in the given equation:

Kc = [NO₂]/([N₂]^(1/2)*[O₂])

Kc = (6 mol/L)/[(10 mol/L)^(1/2)*(20 mol/L)]

Kc = 0.095

Answer: Kc = 0.095

User Caseyburkhardt
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