Answer:
see explanation
Explanation:
(8)
Since PQ = TQ then Δ PQT is isosceles with base angle congruent , so = a = 54 , then
∠ PQT = 180° - 54° - 54° = 180° - 108° = 72°
∠ PQT and b are adjacent angles on a straight line and sum to 180 , then
b = 180 - 72 = 108
∠ RQS = ∠ PQT = 72 ( vertically opposite angles ) , then
c = 180 - 72 - 65 = 180 - 137 = 43
So a = 54, b = 108 , c = 43
(9)
a = 45 ( corresponding angles )
∠ ECD = ∠ ABC = 30° (corresponding angles )
∠ ECD and b are adjacent angles on a straight line and sum to 180° , then
b = 180 - 30 = 150 , so
c = 180 - 30 - 45 = 180 - 75 = 105
So a = 45 , b = 150 , c = 105