Question

Triangle ABC has a right angle at C. Find the length of side BC and AC if

Answer 1

Check the picture below.

`\sin( 70^o )=\cfrac{\stackrel{opposite}{BC}}{\underset{hypotenuse}{10}} \implies 10\sin(70^o)=BC \implies 9.40\approx BC \\\\[-0.35em] ~\dotfill\\\\ \cos(70^o )=\cfrac{\stackrel{adjacent}{AC}}{\underset{hypotenuse}{10}} \implies 10\cos(70^o)=AC \implies 3.42\approx AC`

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