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6) If a system has 48 J of work done on it and absorbs 22 J of heat, what is the value of ΔE for this change?

User Vnk
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1 Answer

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9 votes

ANSWER

ΔE = 70 J

Step-by-step explanation

Given:

• The work done on the system, W = 48 J

,

• The heat absorbed by the system, Q = 22 J

Find:

• The change of energy of the system, ΔE

We will use the convention where:

• Heat transferred to the system: positive (otherwise negative)

,

• Work done on the system: positive (otherwise negative)

By the first law of thermodynamics,


\Delta E=Q+W

Replace with the known values and solve,


\Delta E=22J+48J=70J

Hence, the change in the system's internal energy is 70 J.

User Sijan Bhandari
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