Question

4. A 45 kg boxcar is pushed along a horizontal surface.

At rest at first, the box car is posned a distance of
5.5 m and reaches a speed of 8.0 m/s. Find the
magnitude of the net force on the boxcar.

Answer 1

Step-by-step explanation:

Average velocity = (8-0) / 2 = 4 m/s

to cover 5.5 m would take 5.5 m / 4 m/s = 1.375 s

Accel = change in v / change in t = 8 m/s / 1.375 s = 5.82 m/s^2

F = ma

F = 45 ( 5.82) = 261.8 N