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What is the slope of the line that is perpendicular to y=-3x+13

User Ewindsor
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1 Answer

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Answer:

1/3 is the slope of the line that is perpendicular to y = -3x + 13.

Explanation:

Relationship between the slopes of perpendicular lines:

  • The slopes of perpendicular lines are negative reciprocals of each other.
  • This means we'll first need to identify the slope of y = -3x + 13 before we can find the slope of the other line.

Identifying the slope of y = -3x + 13.

y = -3x + 13 is in the slope-intercept form of a line, whose general equation is given by:

y = mx + b, where:

  • m is the slope,
  • and b is the y-intercept.

Finding the slope of the other line:

If we have two perpendicular lines and know one of the slopes, we can find the slope of the other line using the formula m2 = -1 / m1, where:

  • m1 is the slope of the line we're given,
  • and m2 is the slope of the other line.

Thus, we can find the slope of the other line by substituting -3 for m1 in the perpendicular slope formula:

m2 = -1 / -3

m2 = 1/3

Therefore, the slope of the other line is 1/3.

User Themarcuz
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