Answer:
∑₁⁴ 3n + 5 = option e
∑₁⁴ n² + 3 = option b
∑₂⁵ 2n - 1 = option f
∑₂⁵ 2ⁿ - 5 = option a
Explanation:
∑₁⁴ 3n + 5
= 3(1) + 5 + 3(2) + 5 + 3(3) + 5 + 3(4) + 5
= 8 + 11 + 14 + 17
= option e
∑₁⁴ n² + 3
= 1² + 3 + 2² + 3 + 3² + 3 + 4² + 3
= 4 + 7 + 12 + 19
= option b
∑₂⁵ 2n - 1
= 2(2) - 1 + 2(3) - 1 + 2(4) - 1 + 2(5) - 1
= 3 + 5 + 7 + 9
= option f
∑₂⁵ 2ⁿ - 5
= 2² - 5 + 2³ - 5 + 2⁴ - 5 + 2⁵ - 5
= -1 + 3 + 11 + 27
= option a