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Find the zeros of the function f(x) = 2x² - 10.3x + 11. Round values to the nearest hundredth (if
necessary).

User PhilDulac
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Final answer:

To find the zeros of the function f(x) = 2x² - 10.3x + 11, we set f(x) equal to zero and solve for x using the quadratic formula. The zeros are approximately x = 2.45 and x = 0.9.


Step-by-step explanation:

To find the zeros of a function, we need to determine the values of x that make the function equal to zero. In this case, we have the function f(x) = 2x² - 10.3x + 11. To find the zeros, we set f(x) equal to zero and solve for x.

2x² - 10.3x + 11 = 0

Using the quadratic formula, x = (-b ± sqrt(b²-4ac))/(2a), where a, b, and c are the coefficients of the quadratic equation, we can find the values of x. Plugging in the values from the given function, we have:

x = (-(-10.3) ± sqrt((-10.3)² - 4(2)(11)))/(2(2))

x = (10.3 ± sqrt(106.09 - 88))/4

x = (10.3 ± sqrt(18.09))/4

x ≈ 2.45, 0.9

Therefore, the zeros of the function f(x) = 2x² - 10.3x + 11 are approximately x = 2.45 and x = 0.9, rounded to the nearest hundredth.


Learn more about finding zeros of a quadratic function

User Yoshinori
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