Question

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उक्त AXYZ मा यदि 2ZX = 3Y = 62Z भए सबै
कोणहरूको मान पत्ता लगाउनुहोस् ।In AXYZ
2ZX = 3ZY = 6/Z, find the values of all the angles.
1211227

Answer 1

In triangle AXYZ, the values of the angles are A = 420 degrees, X = 180 degrees, Y = 360 degrees, and Z = 60 degrees.

Step-by-step explanation:

In triangle AXYZ, we are given that 2ZX = 3ZY = 6θZ. Since the sum of the angles in a triangle is always 180 degrees, we can find the value of the angles by setting up equations.

Let's assign angles as follows:

A = θA

X = θX

Y = θY

Z = θZ

Using the given information, we have the following equations:

θZ + θZ + θZ = 180 (Sum of angles in a triangle)

From this equation, we can find θZ:

3θZ = 180

θZ = 60

Now, we can find the other angles using the relationship given:

θY = 6θZ = 6 * 60 = 360 degrees

θX = 3θZ = 3 * 60 = 180 degrees

θA = 180 - (θZ + θY + θX) = 180 - (60 + 360 + 180) = 180 - 600 = -420 degrees

However, angles cannot be negative, so we can disregard the negative sign and find the positive angle:

θA = 420 degrees

Therefore, the values of all the angles are:

A = 420 degrees

X = 180 degrees

Y = 360 degrees

Z = 60 degrees

Learn more about Angles in a triangle