Radius of 1 solid iron sphere =r
→ Volume =34πr3
→ Volume of 27 solid iron
spheres =27x34πr3
→ 34πr'3=27x34πr3
r'3=2πr3
→r'=3r
(ii) Surface area =4+πr2
SA r'=4πr'2
=4π(3r)2=36πr2
S'S=36πr24πr2=91=1:9
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