Question

How many pounds of candy that sells for $0.85 per Ib must be mixed with candy that sells for $1.22 per lb to obtain 9 lb of a mixture that should sell for $0.92 per lb? 50.85-per-lb candy: 73 lb (Type an integer or decimal rounded to two decimal places as needed.) $1.22-per-b candy

Answer 1

This system gives two equations

`(0.85x+1.22y)/(9)=0.92`
`x+y=9`

where x is the number pounds of $0.85/lb candy and y is the number of pounds of $1.22/lb candy.

The solution to the system is

`x=7.297`
`y=1.70`

Hence, 7.297 lb of $0.85 candy is required in order that if we mix them with 1.70 lb of $1.22 candy, we will get a 9 lb solution of 0.92 /lb candy.