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12 + √128
1-√√√2
can be written in the form a +b√2 where a and b are integers.

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Final answer:

To write the expression 12 + √128 1-√√√2 in the form a + b√2, simplify the terms and separate them. Simplify √128 as 8√2, and simplify √√√2 as 1 - 2^(1/16). Then, put these simplified terms together.


Step-by-step explanation:

To write the expression 12 + √128 1-√√√2 in the form a + b√2, we need to simplify it and separate the terms.

For the first term, 12 + √128, we can simplify √128 as √(64 * 2), which becomes 8√2. So, we have 12 + 8√2.

For the second term, 1-√√√2, we need to simplify the nested square roots. Simplifying √√√2 results in √(√(√2)), which is equivalent to √(2^(1/8)), or 2^(1/16). So, we have 1 - 2^(1/16).

Putting these simplified terms together, we have the expression in the form a + b√2 as 12 + 8√2 + (1 - 2^(1/16)).


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