Question

ASAP NEED HELP QUICK I HAVE SCHOOL TMR DUE !! THASNK YOU!

Answer 1

`(x-3)^2-17`

Explanation:

To complete the square for the quadratic expression x² - 6x - 8, begin by adding and subtracting the square of half the coefficient of the x term.

Add it after the x-term to form a perfect square trinomial with the first three terms of the expression, and then subtract it from the constant:

`x^2-6x+\left((-6)/(2)\right)^2-8-\left((-6)/(2)\right)^2`

Simplify:

`x^2-6x+\left(-3\right)^2-8-\left(-3\right)^2`

`x^2-6x+9-8-9`

Group the perfect square trinomial (x² - 6x + 9) and simplify the constants:

`(x^2-6x+9)-17`

To complete the square, factor the perfect square trinomial as a binomial square:

`(x-3)^2-17`

So, the expression x² - 6x - 8, when completed as a square is:

`\Large\boxed{\boxed{(x-3)^2-17}}`